An example of a double salt is

$\underset{{{C}_{3}}{{H}_{6}}C{{l}_{2}}}{\mathop{A}}\,\,\xrightarrow[2.\,\,{{H}^{+}}\,\,(\min d)]{\begin{smallmatrix}
1\,.\,\,alcoholic\,\,KOH\,/\,\Delta \\
followed\,\,by\,\,NaN{{H}_{2}}\,/\,\Delta
\end{smallmatrix}}$ $B\,\xrightarrow[{{H}_{2}}{{O}_{2}}/\overset{\Theta }{\mathop{O}}\,H]{{{B}_{2}}{{H}_{6}}}C$

$A\,\xrightarrow{aq.\,\,KOH\,(excess)}C$

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Assertion : First ionization energy for nitrogen is lower than oxygen.
Reason : Across a period effective nuclear charge decreases.

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The oxidation states of nitrogen in $NO , NO _{2}, N _{2} O$ and $NO _{3}^{-}$ are in the order of :

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Assertion : $RCOCl, (RCO)_2O$ and $RCOOR$’ all react with Grignard reagents to form $3^o$ alcohols.
Reason : $RCOCl$ reacts with $R_2Cd$ to form ketones but $(RCO)_2O$ and $RCOOR'$ do not react at all.

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Hydrolysis of sucrose is glven by the following reactlon.

Sucrose $+$ $H _{2} O \rightleftharpoons$ Glucose $+$ Fructose

If the equilibrium constant $\left( K _{c}\right)$ is $2 \times 10^{13}$ at $300\, K$, the value of $\Delta_{ r } G^{\Theta}$ at the same temperature will be:

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Two $5$ molal solutions are prepared by dissolving a non-electrolyte, non-volatile solute separately in the solvents $X$ and $Y$. The molecular weights of the solvents are $M_X$ and $M_Y$, respectively where $M_X\, = \frac{3}{4} M_Y$. The relative lowering of vapour pressure of the solution in $X$ is $''m''$ times that of the solution in $Y$. Given that the number of moles of solute is very small in comparison to that of solvent, the value of $''m''$ is

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$20\,ml$ of $0.5\,N \,HCl$ and $35 \,ml$ of $0.1\,N \,NaOH$ are mixed. The resulting solution will

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STD 12 - 5. Co-ordination chemistry — JEE STD 11 Science — Question

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