- A$NaCl$
- B${25\,^o}C$
- ✓$AlC{l_3}$
- D$SnC{l_4}$
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$(I)$ $\begin{array}{*{20}{c}}
{C{H_3} - C - {O^ - }} \\
{\,\,\,\,\,\,||\,\,} \\
{\,\,\,\,\,\,O\,\,}
\end{array}$
$(II)$ $CH_3O^-$
$(III)$ ${C_6}{H_5}{O^\Theta }$
$(IV)$ (image)
$\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_2}Cl}\limits_1 $ $\mathop {{{(C{H_3})}_3}C\mathop C\limits^ + HC{H_3}}\limits_2 $ $\mathop {\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}C\mathop C\limits^ + {{(C{H_3})}_2}} \\
{|\,\,\,\,} \\
{Cl\,\,\,}
\end{array}}\limits_3 $ $\mathop {{{(C{H_3})}_2}\mathop C\limits^ + CH{{(C{H_3})}_2}}\limits_4 $
Assertion $(A) :$ Metallic character decreases and non-metallic character increases on moving from left to right in a period.
Reason $(R)$ $:$ It is due to increase in ionisation enthalpy and decrease in electron gain enthalpy, when one moves from left to right in a period.
In the light of the above statements, choose the most appropriate answer from the options given below :