Question
An irrational number between 2 and 2.5 is:
  1. $\sqrt{11}$
  2. $\sqrt{5}$
  3. $\sqrt{22.5}$
  4. $\sqrt{12.5}$

Answer

  1. $\sqrt{5}$
Solution:
$\sqrt{4}=2$ and $\sqrt{6.25}=2.5$
Option (a), (c) and (d): $\sqrt{11},\sqrt{22.5}$ and $\sqrt{12.5},$ all are greater than $\sqrt{6.25}$
⇒ Out of interval (2, 2.5)
Option (b): $\sqrt{4}<\sqrt{5}<\sqrt{6.25}\Rightarrow$ lies in the interval (2, 2.5)
Hence, option (b) is correct.

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