Rajasthan BoardEnglish MediumSTD 9MATHSNumber systems1 Mark
Question
An irrational number between $\sqrt{2}$ and $\sqrt{3}$ is:
✓
Answer
$6^{\frac{1}{4}}$ Solution: An irrational number between a and b is given by $\sqrt{\text{ab}}$ An irrational number between $\sqrt{2}$ and $\sqrt{3}$ is $\sqrt{\sqrt{2}+\sqrt{3}}=\big(\sqrt{6}\big)^{\frac{1}{2}}$ $=6^{\frac{1}{2}\times\frac{1}{2}}$ $=6^{\frac{1}{4}}$ Hence, the correct answer is option (d).
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