Question
An irrational number between $\sqrt{2}$ and $\sqrt{3}$ is:

Answer

  1. $6^{\frac{1}{4}}$
    Solution:
    An irrational number between a and b is given by $\sqrt{\text{ab}}$
    An irrational number between $\sqrt{2}$ and $\sqrt{3}$ is
    $\sqrt{\sqrt{2}+\sqrt{3}}=\big(\sqrt{6}\big)^{\frac{1}{2}}$
    $=6^{\frac{1}{2}\times\frac{1}{2}}$
    $=6^{\frac{1}{4}}$
    Hence, the correct answer is option (d).

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