Question
An irrational number between $\sqrt{2}$ and $\sqrt{3}$ is:
✓
Answer
- $6^{\frac{1}{4}}$
Solution:
$\sqrt{2}$ and $\sqrt{3}$
$=2^{\frac{1}{2}}$ and $3^{\frac{1}{2}}$
$=2^{\frac{2}{4}}$ and $3^{\frac{2}{4}}$
$=4^{\frac{1}{4}}$ and $9^{\frac{1}{4}}$
Irrational between $\sqrt{2}$ and $\sqrt{3}$ is $6^{\frac{1}{4}}$
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