MCQ
An $n.p.n$ transistor with current gain $\beta=100$ in common emitter configuration is shown in figure. The output voltage of the amplifier will be$.....V$
- A$0.1$
- ✓$1.0$
- C$10$
- D$100$
✓
Answer
Correct option: B.
$1.0$
b
$\frac{v_{\text {out }}}{v_{\text {in }}}=\beta \frac{R_{\text {out }}}{R_{\text {in }}}$
$\frac{v_{\text {out }}}{v_{\text {in }}}=\beta \frac{R_{\text {out }}}{R_{\text {in }}}$
$v_{\text {out }}=\frac{100 \times 10 \times 10^{3}}{10^{3}} \times 10^{-3}$
$=1\,V$
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