An object is moving along a straight line with uniform acceleration. The following table gives the velocity of the object at various instants of time: Time (in sec.): 0 1 2 3 4 5 6 Velocity (in m/s): 2 4 6 8 10 12 14 Plot the graph. From the graph, 1. Find the velocity of the object at the end of 2.5 seconds. 2. Calculate the acceleration. 3. Calculate the distance covered in the last 4 seconds.

a= v-u t a=4-2 1 =2m/s^2 Now for, t=2.5 a= v-u t 2= v-2 2.5 5=v-2 v=7

An object is moving along a straight line with uniform accelerati…

Question

An object is moving along a straight line with uniform acceleration. The following table gives the velocity of the object at various instants of time:

Time (in sec.):	0	1	2	3	4	5	6
Velocity (in m/s):	2	4	6	8	10	12	14

Plot the graph.
From the graph,

Find the velocity of the object at the end of 2.5 seconds.
Calculate the acceleration.
Calculate the distance covered in the last 4 seconds.

✓

Answer

$\text{a}=\frac{\text{v}-\text{u}}{\text{t}}$

$\text{a}=\frac{4-2}{1}=2\text{m/s}^2$

Now for,

$\text{t}=2.5$

$\text{a}=\frac{\text{v}-\text{u}}{\text{t}}$

$2=\frac{\text{v}-2}{2.5}$

$5=\text{v}-2$

$\text{v}=7$

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