MCQ
An optically active compound $'X'$ has molecular formula $C_4H_8O_3$. It evolves $CO_2$ with $NaHCO_3. 'X'$ reacts with $LiAlH_4$ to give an achiral compound. $'X'$ is
- A$\begin{matrix}
C{{H}_{3}}C{{H}_{2}}CHCOOH \\
| \\
\,\,\,OH \\
\end{matrix}$ - B$\begin{matrix}
C{{H}_{3}}CHCOOH \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
Me\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ - ✓$\begin{matrix}
C{{H}_{3}}CHCOOH \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\,\,C{{H}_{2}}OH \\
\end{matrix}$ - D$\begin{matrix}
C{{H}_{3}}CHC{{H}_{2}}COOH \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$
