- A

- B

- ✓

- D






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$C{H_3} - CH = O + {C_6}{H_5} - CH =O \xrightarrow[\Delta ]{{\mathop O\limits^\Theta H\,\left( {aq} \right)}}\mathop X\limits_{{\text{(}}{{\text{C}}_4}{{\text{H}}_6}{\text{O)}}} + \mathop Y\limits_{{\text{(}}{{\text{C}}_9}{{\text{H}}_8}{\text{O)}}} $
Statement$-I :\, 2 -$methylbutane on oxidation with $KMnO _{4}$ gives $2 -$methylbutan$-2-$ol.
Statement$-II :$ $n-$alkanes can be easily oxidised to corresponding alcohol with $KMnO _{4}$.
Choose the correct option:
$\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HOCH}\\|\\{HCOH}\\|\\{C{H_2}OH}\\I\end{array}$ $\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HCOH}\\|\\{HOCH}\\|\\{C{H_2}OH}\\{II}\end{array}$ $\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HCOH}\\|\\{HCOH}\\|\\{C{H_2}OH}\\{III}\end{array}$