MCQ
An X-ray machine has an accelerating potential difference of 25,000 volts. By calculation the shortest wavelength will be obtained as (h = $6.63 \times 10^{-34} \mathrm{~J}-\mathrm{sec}$; e =$ 1.6.\times 10^{-19} $ coulomb)
- A0.25 Å
- ✓0.50 Å
- C1.00 Å
- D2.50 Å
