MCQ
Anhydrous sodium acetate on heating with sodalime gives
  • A
    Acetic acid
  • Methane
  • C
    Calcium acetate
  • D
    Ethane

Answer

Correct option: B.
Methane
b
(b) $\mathop {C{H_3}COONa}\limits_{{\rm{Sodium acetate}}}  + NaOH  \xrightarrow{CaO}  \mathop {C{H_4}}\limits_{{\rm{Methane}}}  + N{a_2}C{O_3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

For the following gaseous reaction ${H_2} + {I_2}$ $\rightleftharpoons$ $2HI$, the equilibrium constant
Enthalpy of neutralization of $HCl$ by $NaOH$ is $-\,55.84\,kJ/mol$ and by $NH_4OH$ is $-\,51.34\,kJ/mol$. The enthalpy of ionization of $NH_4OH$ is .....$kJ$
$0.5 \,g$ of hydrocarbon gave $0.9 \,g$ water on combustion. The percentage of carbon in hydrocarbon is
$C{H_3} - CH = C{H_2}\xrightarrow[{(low\,\,conc.)}]{{B{r_2}/hv}}(A)$ ; Product $(A)$ of the reaction is
The incorrect statement regarding $O(SiH_3)_2$ and $OCl_2$ molecule is/are
The $\mathrm{p} \mathrm{K}_{\mathrm{b}}$ of dimethylamine and $\mathrm{pK}_{\mathrm{a}}$ of acetic acid are $3.27$ and $4.77$ respectively at $\mathrm{T}(\mathrm{K})$. The correct option for the $pH$ of dimethylammonium acetate solution is :
When a chemical bond is formed, there is decrease in
$0.1\,M$ $CH_3COOH$ is titrated against $0.1\,M$ $NaOH$. What would be the difference in $pH$ between $1/4$ and $3/4$ stages of neutralisation of acid
On the basis of thermochemical equations (a), (b) and (c), find out which of the algebric relationships given in options (i) to (iv) is correct.

  1. $\text{C}(\text{graphite})+\text{O}_2(\text{g})\rightarrow\text{CO}_2(\text{g});\Delta_\text{r}\text{H}=\text{x}\text{kJ}\ \text{mol}^{-1}$

  2. $\text{C}(\text{graphite})+\frac{1}{2}\text{O}_2(\text{g})\rightarrow\text{CO}(\text{g});\Delta_\text{r}\text{H}=\text{y} \text{kJ}\ \text{mol}^{-1}$

  3. $\text{CO}(\text{g})+\frac{1}{2}\text{O}_2(\text{g})\rightarrow\text{CO}_2(\text{g});\Delta_\text{r}\text{H}=\text{z}\text{kJ}\ \text{mol}^{-1}$

Which of the following is electron rich compound?