MCQ
Any $p-$ orbital can accommodate up to:
- A$4$ electrons
- B$2$ electrons with parallel spins
- C$6$ electrons
- ✓$2$ electrons with opposite spins
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$9\, mol$ $O_2$ and $14\, mol$ $N_2$ here allowed to react. When $3\, mol$ $O_2$ remains unreacted, till then how many moles of $N_2O_3$ would have been produced?
$(A)$ $SnCl _2 \cdot 2 H _2 O$ is a reducing agent.
$(B)$ $SnO _2$ reacts with $KOH$ to form $K _2\left[ Sn ( OH )_6\right]$.
$(C)$ A solution of $PbCl _2$ in $HCl$ contains $Pb ^{2+}$ and $Cl ^{-}$ions.
$(D)$ The reaction of $Pb _3 O _4$ with hot dilute nitric acid to give $PbO _2$ is a redoxreaction.
