MCQ
Aqueous solution of $HCl$ has the $pH = 4$. Its molarity would be
- A$4 \,M$
- B$0.4 \,M$
- ✓$0.0001\, M$
- D$10 \,M$
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$Sn ^{2+}+2 e ^{-} \rightarrow Sn$
$Sn ^{4+}+4 e ^{-} \rightarrow Sn$
The electrode potentials are; $E _{ Sn ^{2+} / Sn }^{\circ}=-0.140\, V$ and $E _{ Sn ^{4+} / Sn }^{\circ}=0.010\, V$. The magnitude of standard electrode potential for $Sn ^{4+} / Sn ^{2+}$ i.e. $E _{ Sn ^{4+} / Sn ^{2+}}^{\circ}$ is $.....\times 10^{-2}\, V$. (Nearest integer)