MCQ
Area bounded by curve $y = k\sin x$ between $x = \pi $ and $x = 2\pi ,$ is
- ✓$2k$ sq. unit
- B$0$
- C$\frac{{{k^2}}}{2}\,\, sq. \,unit$
- D$k\,\, sq. \,unit$
Hence, area $= 2k\,\, sq. \,unit$
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