Area bounded by the ellipse x^2 4 +y^2 9 =1 is - Vidyadip

Question

Area bounded by the ellipse $\frac{x^2}{4}+\frac{y^2}{9}=1$ is

✓

Answer

(a) : Here $a^2=4$ and $b^2=9$.
Since, area of ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ is $\pi a b$ sq. units.
$\therefore \quad$ Required area $=\pi \times 2 \times 3=6 \pi$ sq. units.

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