MCQ
Area bounded by the lines $y = x,\,\,x = - 1,\,\,x = 2$ and $x - $ axis is
- ✓$\frac{5}{2}\,\, sq. \,unit$
- B$\frac{3}{2}\,\, sq. \,unit$
- C$\frac{1}{2}\,\, sq. \,unit$
- DNone of these
$= \int_{ - 1}^0 {\,y\,.\,dx + \int_0^2 {y\,.\,dx = \frac{5}{2}} } \,\, sq. \,unit$.
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If $I_1 = \int\limits_{\frac{\pi }{6}}^{\frac{\pi }{3}} \, f (\tan\, \theta + \cot\, \theta )\cdot sec^2\, \theta\, d\, \theta$ &
$I_2 = \int\limits_{\frac{\pi }{6}}^{\frac{\pi }{3}} \, f (\tan\, \theta + \cot\, \theta )\cdot cosec^2\, \theta\, d \, \theta$ ,
then the ratio $\frac{{{I_1}}}{{{I_2}}}$ :
The domain of the function cos-1(2x - 1) is:
$[0,1]$
$[-1,1]$
$(-1,1)$
$[0,\pi]$