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Heron’s Formula — MATHS STD 9 — Question

Rajasthan BoardEnglish MediumSTD 9MATHSHeron’s Formula1 Mark
Question
Area of the given triangle is:
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Answer

In the given triangle,
$\text{Base}(\text{BC})=\sqrt{13^2-12^2}=\sqrt{169-144}=5 \ \text{cm}$
Area of triangle $ABC =\frac{1}{2}\times\text{BC}\times\text{AB}$
$=\frac{1}{2}\times5\times12$
$=30\text{ sq.cm}$

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