Question
Arrange the elements with the following electronic configurations in order of increasing electron gain enthalpy.
  1. 1s2 2s2 2p5
  2. 1s2 2s2 2p4
  3. 1s2 2s2 2p3
  4. 1s2 2s2 2p6 3s2 3p4

Answer

Out of F(1s2 2s2 2p5), O(1s2 2s2 2p4), N(1s2 2s2 2p3) and S(1s2 2s2 2p6 3s2 3p4), only N has positive electron gain enthalpy because of its stable exactly half-filled electronic configuration while all others have negative electron gain enthalpies. Since, F needs only one more electron to acquire the nearest inert gas configuration, therefore, it has the most negative electron gain enthalpy. Out of O and S, O has less negative electron gain enthalpy than S because of electron-electron repulsions present in its small compact 2p-orbital. Thus, overall order of increasing electron gain enthalpy is: (i) < (iv) < (ii) < (iii).

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