- ASaccharine
- ✓Aspartame
- CSucralose
- Dalitame
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$\begin{array}{*{20}{c}}
{C{H_2} - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - COOH}
\end{array}\xrightarrow{\Delta }(A)\xrightarrow{{C{H_3} - C{H_2}N{H_2}/\Delta }}(B)$
$(B)$ will be :
$Pt ( s )\left| H _{2}( g , 1 bar )\right| HCl ( aq \cdot, pH =1)| AgCl ( s )| Ag ( s )$
The $pH$ of aq. HCl required to stop the photoelectric current from $K \left( w _{0}=2.25 eV \right),$ all other conditions remaining the same, is..........$\times 10^{-2}$ (to the nearest integer).
Given, $2.303 \frac{ RT }{ F }=0.06 V ; E _{ AgC1|Ag|C ^{-}}^{0}=0.22\, V$

Use : $\frac{{2.303RT}}{F}$ = $0.06$
Ratio of moles of formic acid obtained in reaction $(i)$ and reaction $(ii)$ is