MCQ
As per Bohr model, the minimum energy (in $eV$ ) required to remove an electron from the ground state of doubly ionized $L i$ atom $(Z=3)$ is
- A$1.51$
- B$13.6$
- C$40.8$
- ✓$122.4$
✓
Answer
Correct option: D.
$122.4$
$E=-Z^2 \times 13.6 \mathrm{eV}=-9 \times 13.6 \mathrm{eV}=-122.4 \mathrm{eV}$
So ionisation energy $=+122.4 \mathrm{eV}$.
So ionisation energy $=+122.4 \mathrm{eV}$.
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