MCQ
Assertion $(A) :$ If $(\vec{a} \times \vec{b})^2+(\vec{a} \cdot \vec{b})^2=400$ and $|\vec{a}|=4$, then $|\vec{b}|=9$.
Reason $(R) :$ If $\vec{a}$ and $\vec{b}$ are any two vectors, then $(\vec{a} \times \vec{b})^2$ is equal to $|\vec{a}|^2|\vec{b}|^2-(\vec{a} \cdot \vec{b})^2$.
  • A
    Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A).$
  • B
    Both $(A)$ and $(R)$ are true but $(R)$ is not the correct explanation of $(A).$
  • C
    $(A)$ is true but $(R)$ is false.
  • $(A)$ is false but $(R)$ is true.

Answer

Correct option: D.
$(A)$ is false but $(R)$ is true.
$(\vec{a} \times \vec{b})^2+(\vec{a} \cdot \vec{b})^2=400,|\vec{a}|=4$
Now, $(\vec{a} \times \vec{b})^2+(\vec{a} \cdot \vec{b})^2=|\vec{a}|^2|\vec{b}|^2$
$\Rightarrow 400=(4)^2|\vec{b}|^2 \Rightarrow 16|\vec{b}|^2=400$
$\Rightarrow|\vec{b}|^2=25 \Rightarrow|\vec{b}|=5$
Hence, assertion is false.
$(\vec{a} \times \vec{b})^2+(\vec{a} \cdot \vec{b})^2=|\vec{a} \times \vec{b}|^2+(\vec{a} \cdot \vec{b})^2$
$=(|\vec{a}||\vec{b}| \sin \theta)^2+(|\vec{a}||\vec{b}| \cos \theta)^2=|\vec{a}|^2|\vec{b}|^2$
$\Rightarrow(\vec{a} \times \vec{b})^2=|\vec{a}|^2|\vec{b}|^2-(\vec{a} \cdot \vec{b})^2$
Hence, reason is true.

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