Reason : The surface density of charge onthe plate remains constant or unchanged.
Energy stored inthe capacitor $\mathrm{U}=\frac{1}{2} \mathrm{CV}^{2}$
When a dielectric slab of dielectric constant
$\mathrm{K}$ is introduced between the plates of the
condenser, then $\mathrm{C} \longrightarrow \mathrm{KC}$
So energy stored will become $K$ times.
since $Q=C V,$ So $Q$ will become $K$ times
$\therefore $ Surface charge density
$\sigma^{\prime}=\frac{\mathrm{KQ}}{\mathrm{A}}=\mathrm{K} \sigma_{0}$
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[Given: The acceleration due to gravity $g=10 \mathrm{~ms}^{-2}$ and $\pi=3.14$ ]
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($1$) Considering the air flow to be streamline, the steady mass flow rate of air exiting the chimney is
. . . . .$\mathrm{gm} \mathrm{s}^{-1}$.
($2$) When the chimney is closed using a cap at the top, a pressure difference $\Delta P$ develops between the top and the bottom surfaces of the cap. If the changes in the temperature and density of the hot air, due to the stoppage of air flow, are negligible then the value of $\Delta P$ is. . . . .$\mathrm{Nm}^{-2}$.
