Question
Assertion : An electric bulb is first connected to a dc source and then to a ac source having the same brightness in both the cases.
Reason : The peak value of voltage for an A.C. source is $\sqrt{2}$ times the root mean square voltage.

Answer

(e) Voltage of dc source is constant but in ac, peak value of voltage is $\sqrt{2}$ times the $r m s$. voltage. Hence bulb will glow with more brightness when connected to an ac source of the same voltage.

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