Assertion : Bending a wire does not effect electrical resistance.
Reason : Resistance of wire is proportional ot resistivity of material.
AIIMS 2016, Easy
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Resistance wire $R = \rho \frac {I}{A}$, where $\rho $ is resistivity of material which does not depend on the geometry of wire. Since when wire is bent resistivity, length and area of cross-section do not change, therefore resistance of wire also remain same.
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In the circuit shown below, the switch $S$ is connected to position $P$ for a long time so that the charge on the capacitor becomes $q _1 \mu C$. Then $S$ is switched to position $Q$. After a long time, the charge on the capacitor is $q _2 \mu C$.
The actual value of resistance $R$, shown in the figure is $30\,\Omega $. This is measured in an experiment as shown using the standard formula $R = \frac{V}{I}$ where $V$ and $I$ are the readings of the voltmeter and ammeter, respectively. If the measured value of $R$ is $5\%$ less, then the internal resistance of the voltmeter is ................. $\Omega$
If resistance of voltmeter is $10000 \,\Omega$ and resistance of ammeter is $2 \,\Omega$ then find $R$ when voltmeter reads $12\,V$ and ammeter reads $0.1\, A$ ............... $\Omega$
The charge flowing in a conductor varies with time as $Q = at -bt^2$. Then for current, which statement is incorrect.
$(A)$ decreases linearly with time
$(B)$ reaches a maximum and then decreases
$(C)$ fall to zero after time $t = a/2b$
$(D)$ changes at a rate $-2b$
Options :