- A$100 \,ml $ of $0.01\,\,M\,\,HCl$
- B$100 \,ml $ of $0.01\,\,M\,\,{H_2}S{O_4}$
- CMixture of $50 \,ml$ of $0.02\,M\,H_2SO_4$ and $50\,ml$ of $0.02\,M\,NaOH$
- ✓$(a)$ and $(c)$ both
$pH = 3$
M.eq. of $0 .02$ $M\,\,{H_2}S{O_4} = \frac{{.04 \times 50}}{{1000}} = 2 \times {10^{ - 3}}$
M.eq. of $0.02$ $M\,\,NaOH = \frac{{0.02 \times 50}}{{1000}} = 1 \times {10^{ - 3}}$
Left $[{H^ + }] = 2 \times {10^{ - 3}} - 1 \times {10^{ - 3}} = 1 \times {10^{ - 3}}$;$pH = 3$
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$(i)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}OH}}$ $ (CH_3)_2CH - CH_2OC_2H_5 + HBr$
$(ii)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}O^-}} $ $(CH_3)_2CH - CH_2OC_2H_5 + Br^-$
The mechanisms of reactions $(i)$ and $(ii)$ are respectively

$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - C - CH - CHO} \\
{\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,CN}
\end{array}$
is :