MCQ
At which points the function$f(x) = \frac{x}{{[x]}}$, where$[.]$ is greatest integer function, is discontinuous
  • A
    Only positive integers
  • All positive and negative integers and $(0, 1)$
  • C
    All rational numbers
  • D
    None of these

Answer

Correct option: B.
All positive and negative integers and $(0, 1)$
b
(b) $(i)$ When $0 \le x < 1$

$f(x)$ doesn't exist as $[x] = 0$ here.

$(ii)$ Also $\mathop {\lim }\limits_{x \to 1 + } f(x)$ and $\mathop {\lim }\limits_{x \to 1 - } f(x)$ does not exist.

Hence $f(x)$ is discontinuous at all integers and also in $(0, 1).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If $f(a+b+1-x)=f(x),$ for all $x,$ where $a$ and $b$ are fixed positive real numbers, then $\frac{1}{a+b} \int\limits_{a}^{b} x(f(x)+f(x+1)) d x$ is equal to 
Let $f$ be a differentiable function defined on $\left[0, \frac{\pi}{2}\right]$ such that $f(x) > 0$ and $f(x)+\int \limits_0^x f(t) \sqrt{1-\left(\log _e f(t)\right)^2} d t=e, \forall x \in\left[0, \frac{\pi}{2}\right]$ Then $\left(6 \log _{ e } f \left(\frac{\pi}{6}\right)\right)^2$ is equal to $.............$
The function $\text{f(x)}=\begin{cases}\frac{\sin3\text{x}}{\text{x}},&\text{x}\ne0\\\frac{\text{k}}{2},&\text{x}=0\end{cases}$ is continuous at x = 0, then k =
  1. 3
  2. 6
  3. 9
  4. 12
$\int\frac{\cos2\text{x}-\cos2\theta}{\cos\text{x}-\cos\theta}\text{dx}$  is equal to:
  1. $2(\sin\text{x}+\text{x}\cos\theta)+\text{c}$
  2. $2(\sin\text{x}-\text{x}\cos\theta)+\text{c}$
  3. $2(\sin\text{x}+2\text{x}\cos\theta)+\text{c}$
  4. $2(\sin\text{x}-2\text{x}\cos\theta)+\text{c}$
If $\vec u$ and $\vec v$ are unit vectors and $\theta$ is the acute angle between them, then $2 \vec u \times 3 \vec v$ is a unit vector for
Find the principal values of: $\sin ^{-1}\left(\frac{-1}{2}\right)$
Let $f : [1, 3] \to R$ be a function satisfying $\frac{x}{{[x]}} \le f(x) \le \sqrt {6 - x} ,$ for all $x \ne 2$ and $f(2) = 1,$ where $R$ is the set of all real numbers and $[x]$ denotes the largest integer less than or equal to $x.$

Statement $1:$ $\mathop {\lim }\limits_{x \to {2^ - }} \,f(x)$ exists.

Statement $2:$ $f$ is continuous at $x = 2.$

A bag X contains 2 white and 3 black balls and another bag Y contains 4 white and 2 black balls. One bag is selected at random and a ball is drawn from it. Then, the probability chosen to be white is,
  1. $\frac{2}{15}$
  2. $\frac{7}{15}$
  3. $\frac{8}{15}$
  4. $\frac{14}{15}$
If $\text{y}=\text{a}+\text{bx}^2,\text{a,b}$ arbitrary constants, then
  1. $\frac{\text{d}^2\text{y}}{\text{dx}^2}=2\text{xy}$
  2. $\text{x}\frac{\text{d}^2\text{y}}{\text{dx}^2}=\text{y}_1$
  3. $\text{x}\frac{\text{d}^2\text{y}}{\text{dx}^2}-\frac{\text{dy}}{\text{dx}}+\text{y}=0$
  4. $\text{x}\frac{\text{d}^2\text{y}}{\text{dx}^2}=2\text{xy}$
If $\text{f(x)}=\begin{cases}\frac{1-\cos10\text{x}}{\text{x}^2},&\text{x}<0\\\text{a},&\text{x}=0\\\frac{\sqrt{\text{x}}}{\sqrt{625+\sqrt{\text{x}}}-25},&\text{x}>0\end{cases}$ then the value of so that f(x) may be continuous at x = 0 is:
  1. 25
  2. 50
  3. -25
  4. none of these