MCQ
$BCl_3 + H_2O \longrightarrow$ Product, here product
- ✓$H_3BO_3 + HCl$
- B$B_2O_3 + HOCl$
- C$B_2H_6 + HCl$
- D$B_2O_3 + HCl$
The products formed in the reaction are $H _3 BO _3+3 HCl$.
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| Substance | $H _{2}$ | $C ($ graphite $)$ | $C _{2} H _{6}( g )$ |
| $\frac{\Delta_{ C } H ^{\Theta}}{ kJmol ^{-1}}$ | $-286.0$ | $-394.0$ | $-1560.0$ |
The enthalpy of formation of ethane is ........ .
Product in above reaction is