- A$M{g^{2 + }}$
- B$N{a^ + }$
- ✓$L{i^ + }$
- D${H^ + }$
Both contain $2$ electrons.
They have an electronic configuration $Be ^2=1 s ^2= Li ^{+}$.
This is equal to the electronic configuration of $He$.
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[Atomic number: $S =16, C 1=17, I =53$ and $Xe =54$ ]

(figure) $\xrightarrow[{(2)\,Zn}]{{(1)\,{O_3}}}\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,O\,\,\,\,\,\,\,O\,\,} \\
{\,||\,\,\,\,\,\,\,\,\,||} \\
{H - C - C - H}
\end{array}}\limits_{Glyoxal} + $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,O\,\,\,\,\,O\,\,} \\
{\,||\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - C - C{H_3}}
\end{array}}\limits_{2,3 - Bu\tan edione} + \mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,O\,\,\,\,\,O} \\
{\,\,\,\,\,\,||\,\,\,\,\,\,||} \\
{C{H_3} - C - C - H}
\end{array}}\limits_{Pyrualdehyde} $