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STD 11 -p-Block elements - I — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 -p-Block elements - I4 Marks
MCQ
$BeCl _{2}$ reacts with $LiAlH _{4}$ to give ....
  • A
    $Be + Li \left[ AlCl _{4}\right]+ H _{2}$
  • B
    $Be + AlH _{3}+ LiCl + HCl$
  • ✓
    $BeH _{2}+ LiCl + AlCl _{3}$
  • D
    $BeH _{2}+ Li \left[ AlCl _{4}\right]$
✓

Answer

Correct option: C.
$BeH _{2}+ LiCl + AlCl _{3}$
c
$2 BeCl _{2}+ LiAlH _{4} \rightarrow 2 BeH _{2}+ LiCl + AlCl _{3}$

This is the method to prepare $BeH _{2}$

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