MCQ
$\begin{array}{*{20}{c}}
  {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {Et - {\text{ }}O - {\text{ }}C - {\text{ }}O - {\text{ }}Et\xrightarrow[{(2){H_3}{O^ \oplus }}]{{\left( 1 \right){\text{ }}C{H_3}MgBr\,\,\left( {excess} \right)}}(A),} 
\end{array}$

 Product $(A)$ is 

  • A
    $\begin{array}{*{20}{c}}
      {O\,\,\,\,\,\,\,\,\,} \\ 
      {||\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - {\text{  }}C - {\text{ }}O - {\text{ }}Et} 
    \end{array}$
  • B
    $\begin{array}{*{20}{c}}
    {\,\,\,O}\\
    {\,\,\,||}\\
    {C{H_3} - {\rm{  }}C - {\rm{ }}C{H_3}}
    \end{array}$
  • $\begin{array}{*{20}{c}}
    {\,\,\,\,\,\,OH}\\
    {\,|}\\
    {C{H_3} - {\rm{  }}C - {\rm{ }}C{H_3}}\\
    {\,|}\\
    {\,\,\,\,\,\,\,C{H_3}}
    \end{array}$
  • D
    ${C{H_3} - {\rm{  }}C{H_2} - {\rm{ }}C{H_3}}$

Answer

Correct option: C.
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,OH}\\
{\,|}\\
{C{H_3} - {\rm{  }}C - {\rm{ }}C{H_3}}\\
{\,|}\\
{\,\,\,\,\,\,\,C{H_3}}
\end{array}$
c

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