STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

$N{O_2} + {F_2}\xrightarrow{{slow}}N{O_2}F + F$

$N{O_2} + F\xrightarrow{{fast}}N{O_2}F$

Thus rate expression of the above reaction can be written as

Assertion $(A)$: Cis form of alkene is found to be more polar than the trans form

Reason $(R)$: Dipole moment of trans isomer of $2$-butene is zero.

In the light of the above statements, choose the correct answer from the options given below :