MCQ
$Be's$ $4^{th}$ electron will have four quantum numbers
$n$ $l$ $m$ $s$
- A$1$ $0$ $0$ $+1/2$
- B$1$ $1$ $+1$ $+1/2$
- ✓$2$ $0$ $0$ $-1/2$
- D$2$ $1$ $0$ $+1/2$
$n$ $l$ $m$ $s$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(a)\,B{r_2}(l) \to B{r_2}(g)$
$(b)\,{H_2}O(s) \to {H_2}O(g)$
$(c)\,{N_2}\,\left[ {1\,atm,\,{{100}\,^o}C} \right] \to {N_2}\,\left[ {1\,atm,\,{{150}\,^o}C} \right]$
$(d)\,{N_2}\,(g) + 3{H_2}(g) \to 2N{H_3}(g)$
$(e)\,CaC{O_3}(s) \to CaO(s) + C{O_2}(g)$