MCQ
$\Big(-\frac{5}{7}\Big)^{-5}$ is equal to:
  • A
    $\Big(-\frac{5}{7}\Big)^{-5}$
  • B
    $\Big(\frac{5}{7}\Big)^5$
  • C
    $\Big(\frac{7}{5}\Big)^5$
  • $\Big(\frac{-7}{5}\Big)^5$

Answer

Correct option: D.
$\Big(\frac{-7}{5}\Big)^5$
Using law of exponents, $\text{a}^{-\text{m}}=\frac{1}{\text{a}^\text{m}} [\because$ a is non$-$zero integer$]$
$\therefore$ $\Big(-\frac{5}{7}\Big)^5=\frac{1}{​​\Big(\frac{-5}{7}\Big)^5}$
$=\Big(-\frac{7}{5}\Big)^5$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free