Question
$\big(6+\sqrt{27}\big)-\big(3+\sqrt{3}\big)+\big(1-2\sqrt{3}\big)$ when simplified is:
✓
Answer
- positive and rational.
Solution:
$\big(6+\sqrt{27}\big)-\big(3+\sqrt{3}\big)+\big(1-2\sqrt{3}\big)$
$=6+\sqrt{27}-3-\sqrt{3}-2\sqrt{3}$
$=6-3+3\sqrt{3}-\sqrt{3}-2\sqrt{3}$
$=3$
which is positive and rational number.
Hence, the correct answer is option (b).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The point (0, 9) lies.
The quadrilateral formed by joining the midpoints of the sides of a quadrilateral ABCD, taken in order, is a rhombus, if:
- ABCD is a Parallelogram.
- ABCD is rhombus.
- Diagonals of ABCD are equal.
- Diagonals of ABCD are perpendicular to each other.
The value of $\Big(\frac{12^{\frac{1}{5}}}{27^{\frac{1}{5}}}\Big)^{\frac{5}{2}}.$
→For drawing a frequency polygon of a continuous frequency distribution, we plot the points whose ordinates are the frequency of respective classes and abscissa are respectively:
If the height and radius of a cone of volume V are doubled, then the volume of the cone, is:
- 3V
- 4V
- 6V
- 8V
Which one of the following is not equal to $\big(\sqrt[3]{8}\big)^{-\frac{1}{2}}?$
→- $\big(\sqrt[3]{2}\big)^{-\frac{1}{2}}$
- $8^{-\frac{1}{6}}$
- $\frac{1}{\big(\sqrt[3]{8}\big)^\frac{1}{2}}$
- $\frac{1}{\sqrt{2}}$
Write the correct answer in the following:
The number of dimensions, a solid has:
The number of dimensions, a solid has:
- 1
- 2
- 3
- 0
The lengths of the three sides of a triangular are $30\ cm, 24\ cm$ and $18\ cm$ respectively. The length of the altitude of the triangle corresponding to the smallest side is:
→