MCQ
Bleaching action of $S{O_2}$ is due to
- ✓Reduction
- BOxidation
- CHydrolysis
- DIts acidic nature
Coloured flower $ + \,2[H] \to $Colourless flower
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$[(\eta^5 - C_5H_5) Fe(CO)_2Cl]$ is
$\begin{array}{*{20}{c}}
{C{H_3} - CH - COOH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{\Delta }[Y]$
$[Y]$ will be :