MCQ
Bond line formula of $HOCH$ $({CN})_2$ is:
- A

- B

- C

- ✓







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$A.$ $CH _3 COOH$
$B.$ $F _3 C - COOH$
$C.$ $ClCH _2- COOH$
$D.$ $FCH _2- COOH$
$E.$ $BrCH _2- COOH$
Choose the correct answer from the options given below:
Assertion $(A):$ $\mathrm{H}_2 \mathrm{Te}$ is more acidic than $\mathrm{H}_2 \mathrm{~S}$.
Reason $(R):$ The bond dissociation enthalpy of $\mathrm{H}_2 \mathrm{Te}$ is less than that of $\mathrm{H}_2 \mathrm{~S}$.
In the context of the above statements, choose the correct answer from the following options:
(image) $\frac{{conc.\,HN{O_3}}}{{conc.\,{H_2}S{O_4}}}X$
the structure of the major product $'X'$ is