MCQ
Boric acid in solid, whereas $BF _3$ is gas at room temperature because of
- AStrong ionic bond in Boric acid
- BStrong van der Waal's interaction in Boric acid
- ✓Strong hydrogen bond in Boric acid
- DStrong covalent bond in $BF _3$
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$N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$ is $K,$ the equilibrium constant for $\frac{1}{2} N_{2(g)} + \frac{1}{2} O_{2(g)} \rightleftharpoons NO_{(g)}$ will be
$C{H_3}C \equiv \,CC{H_3}\,\xrightarrow[{{\text{heat}}}]{{NaN{H_2}/{\text{inert solvent}}}}P$
$[A]$ $4$-methylchlorobenzene $[B]$ $4$-chlorotoluene $[C]$ $1$-chloro-$4$-methylbenzene $[D]$ $1$-methyl-$4$-chlorobenzene