Question
Bring out the following conversion:
Benzoic acid to Benzamide.
Benzoic acid to Benzamide.
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methoxybenzene.
The methyl hemiacetal of formaldehyde.
$\text{H}_3\text{C}-\text{CH}-\text{CH}_2-\text{CH}-\text{CH}-\text{CH}_2-\text{CH}_3\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \ \ \ \ \ \ \ \ \ |\\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\ \ \ \ \ \text{C}_2\text{H}_5$