Question
By using the properties of definite integral, evaluate the integral in Exercise:
$\int\limits_{2}^{8}|\text{x}-5|\ \text{dx}$

Answer

$\text{Let}\ \text{I}=\int\limits_{2}^{8}|\text{x}-5|\ \text{dx}$

$\text{putting}\ \text{x}-5=0\ \ \Rightarrow\ \text{x}=5\in(2,8)$

$\therefore\ \ \text{from eq. (i)},\ \text{I}=\int\limits_{2}^{5}|\text{x}-5|\ \text{dx}+\int\limits_{5}^{8}|\text{x}-5| \text{dx}$

$=\int\limits_{2}^{5}-(\text{x}-5)\ \text{dx}+\int\limits_{5}^{8}(\text{x}-5)\text{dx}$

$=-\bigg(\frac{\text{x}^{2}}{2}-5\text{x}\bigg)^{-2}_{-5}+\bigg(\frac{\text{x}^{2}}{2}-5\text{x}\bigg)^{5}_{-2}$

$=-\bigg[\bigg(\frac{25}{2}-25\bigg)-(10-2)\bigg]+\bigg[(32-40)-\bigg(\frac{25}{2}-25\bigg)\bigg]$

$=25-\frac{25}{2}-8-8-\frac{25}{2}+25=34-\frac{50}{2}=34-25=9$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Prove the following results
$\cos\Big(\sin^{-1}\frac{3}{5}+\cot^{-1}\frac{3}{2}\Big)=\frac{6}{5\sqrt{13}}$
If $\vec{\text{a}},\vec{\text{b}},\vec{\text{c}}$ are three unit vectors such that $\vec{\text{a}}\times\vec{\text{b}}=\vec{\text{c}},\vec{\text{b}}\times\vec{\text{c}}=\vec{\text{a}},\vec{\text{c}}\times\vec{\text{a}}=\vec{\text{b}}.$Show that $\vec{\text{a}},\vec{\text{b}},\vec{\text{c}}$ from an orthonormal right handed triad of unit vectors.
Find the particular solution of the differential equation $\frac { d y } { d x } - 3 y \cot x = \sin 2 x$ , given that y = 2 when $x = \frac { \pi } { 2 }$.
Evaluate the following:
$\int\limits^1_0\frac{\text{x}}{\sqrt{1+\text{x}^2}}\text{dx}$
If x and y are connected parametrically by the equations given in Exercise without eliminating the parameter, Find $\frac{\text{dy}}{\text{dx}}.$
$\text{x}=\text{a}(\theta-\sin\theta),\text{y}=\text{a}(1+\cos\theta)$
Prove the following:

$\cos^{-1}\Bigg(\frac{12}{13}\Bigg)+\sin^{-1}\Bigg(\frac{56}{65}\Bigg)$.

Prove the following:  $\cot^{-1}\Bigg[\frac{\sqrt{\text{1 + sin x}}+\sqrt{\text{1 - sin x}}}{\sqrt{\text{1 + sin x }}-\sqrt{\text{1 - sin x}}}\Bigg]=\frac{\text{x}}{2},\text{x}\in\Bigg(0,\frac{\pi}{4}\Bigg)$.
Give an example of a relation which is,
Reflexive and symmetric but not transitive.
Given $\text{A}=\begin{bmatrix}2 & -3 \\-4 & 7 \end{bmatrix},$ compute A-1 and show that 2A-1 = 9I - A.
Discuss the applicability of the Rolle's theorem for the following function on the indicated interval
$\text{f}(\text{x})=[\text{x}]\text{ for }-1\leq\text{x}\leq1,$ where [x] denotes the greatest integer not exceeding x.