MCQ
By which mechanism does the above reaction proceed?
- AE1
- BE2
- CE1cb
- D$\gamma$-Elimination
✓
Answer
- E2
Explanation:
If the reaction proceeds by E1 mechanism, then the breaking of C−H and C−D bonds is not involved in the slow step (or rate determining effect). Based on this both products CH2=CH−CD3 and CH3−CH=CD2 are expected.
However only CH2=CH−CD3 is obtained. This indicates that breaking of C−H bond (which is faster than breaking of C−D bond) is involved in the mechanism along-with breaking of C−Br bond.
This indicates E2 mechanism for elimination.
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