MCQ
c $C - C$ single bond of $HC \equiv C - CH = C{H_2}$ is
- A$s{p^3} - s{p^3}$
- B$s{p^2} - s{p^3}$
- ✓$sp - s{p^2}$
- D$s{p^3} - sp$
✓
Answer
Correct option: C.
$sp - s{p^2}$
c
Therefore, The hybridization of carbon atoms in the $C - C$ single bond of $HC \equiv C - CH = CH _2$ is $sp - sp ^2$ because the right side of carbon having another side triple bond so it is $sp$ hybridized whereas left side carbon having double bond $sp$ it is $sp ^2$ hybridized.
Therefore, The hybridization of carbon atoms in the $C - C$ single bond of $HC \equiv C - CH = CH _2$ is $sp - sp ^2$ because the right side of carbon having another side triple bond so it is $sp$ hybridized whereas left side carbon having double bond $sp$ it is $sp ^2$ hybridized.
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