- A${C_2}{H_2}$
- B${C_2}{H_4}$
- ✓${C_2}{H_6}$
- D${C_2}{H_2}B{r_2}$
We can also understand the bond length with the help of the $s$ character.
Higher the $s$-character lesser is the bond length.
This is because higher $s$ character implies that the electrons that are bonded pairs are closely held together, thus making the bond length small as well as strong.
Hybridisation of $C _2 H _6$ is $sp ^3$
The $s$ character in $C _2 H _6$ (Ethane) is: $\frac{1}{4} \times 100=25 \,\%$ which is the least amongst the other given compounds.
Therefore the $C - H$ bond length of $C _2 H _6$ is the longest.
Hence it is the correct option.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$2MnO_4^ - + 10{I^ - } + 16{H^ + } \to 2M{n^{2 + }} + 5{I_2} + 8{H_2}O$
The rate of appearance $I_2$ is......$\times {10^{ - 2}}\,M{s^{ - 1}}$

$\begin{array}{*{20}{c}}
\,\,\,{{C_2}{H_5}} \\
{|\,\,\,\,\,\,\,} \\
{C{H_3} - C - COOH} \\
{|\,\,\,\,\,\,} \\
\,\,\,{{C_3}{H_7}}
\end{array}\xrightarrow{{{N_3}H/Conc.\,{H_2}S{O_4}}}\begin{array}{*{20}{c}}
\,\,\,\,\,\,\,\,\,{{C_2}{H_5}} \\
| \\
{C{H_3} - C - N{H_2}} \\
| \\
\,\,\,\,\,\,\,\,\,{{C_3}{H_7}}
\end{array}$
is called :
