MCQ
$C$ will be


- A

- ✓

- C

- D








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$(1)\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,C{H_3}} \\
| \\
{{C_2}{H_5}C{H_2}C - OC{H_3}} \\
| \\
{\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(2)\,\,\begin{array}{*{20}{c}}
{{C_2}{H_5}C{H_2}C = C{H_2}} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(3)\,\,\begin{array}{*{20}{c}}
{{C_2}{H_5}CH = C - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$Pt|Cl_2| Cl^-(1\,M) ||Cl^-(1\,M)|Cl_2|Pt$
$P_1\, atm$ $P_2\, atm$


