MCQ
${C_2}{H_5}OH$ can be differentiated from $C{H_3}OH$ by
- AReaction with $HCl$
- BReaction with $N{H_3}$
- ✓By iodoform test
- DBy solubility in water
✓
Answer
Correct option: C.
By iodoform test
c
(c) ${{C}_{2}}{{H}_{5}}OH\underset{{{I}_{2}}}{\mathop{\xrightarrow{NaOH}}}\,CH{{I}_{3}}$ yellow ppt.
(c) ${{C}_{2}}{{H}_{5}}OH\underset{{{I}_{2}}}{\mathop{\xrightarrow{NaOH}}}\,CH{{I}_{3}}$ yellow ppt.
$C{{H}_{3}}OH\underset{{{I}_{2}}}{\mathop{\xrightarrow{NaOH}}}\,$ No reaction
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