MCQ
Calculate crystal field stabilization energy in $[Co(CN)_6]^{3-}$
- ✓$ - 2.4\,{\Delta _0} + 2p$
- B$ + 2.4\,{\Delta _0} + 2p$
- C$ - 3.6{\Delta _0} + 2p$
- D$ - 1.8\,{\Delta _0} + 2p$
$\Delta=$ no. of electrons in $t _{2 g } \cdot(-0.4)+$ no. of electrons in $e _{ g }(0.6)$
$=6(-0.4)+0(0.6)$
$=-2.4 \Delta_0$
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| List$-I$ | List$-II$ |
| $A$ $16\,g \text { of } CH _{4( g )}$ | $I$ Weighs $28\,g$ |
| $B$ $1\,g \text { of } H _{2( g )}$ | $II$ $60.2 \times 10^{23}$ electrons |
| $C$ $1\,mole \text { of } N _{2( g )}$ | $III$ Weighs $32\,g$ |
| $D$ $0.5\,mol$ of $SO _{2( g )}$ | $IV$ Occupies $11.4\,L$ volume at STP |
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