Question
Calculate $T_1$ and $T_2$
✓
Answer
$\frac{\mathrm{T}_{1}}{\sin 120^{\circ}}=\frac{\mathrm{Mg}}{\sin 90^{\circ}}$
$\mathrm{T}_{1}=\frac{\sqrt{3}}{2} \mathrm{Mg}$
$\frac{\mathrm{T}_{2}}{\sin 150^{\circ}}=\frac{\mathrm{Mg}}{\sin 90^{\circ}}$
$\mathrm{T}_{2}=\frac{\mathrm{Mg}}{2}$
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