Calculate the equivalent weight of KMnO _4 in 1. Acidic medium 2. Basic medium 3. Neutral medium

1. Equivalent weight of KMnO _4 in acidic medium = Molecular weight of KMnO _4 No. of moles of electrons transferred 2. Equivalent weight of KMnO _4 in basic medium = Molecular weight of KMnO _4 No. of moles of electrons transferred 3. Equivalent weight of KMnO _4 in neutral medium = Molecular weight of KMnO _ 4 No. of moles of electrons transferred

Calculate the equivalent weight of KMnO _4 in 1. Acidic medium 2.…

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Question

Calculate the equivalent weight of $KMnO _4$ in

Acidic medium
Basic medium
Neutral medium

✓

Answer

1. Equivalent weight of $KMnO _4$ in acidic medium
$
=\frac{\text { Molecular weight of } KMnO _4 \text { }}{\text { No. of moles of electrons transferred }}
$
2. Equivalent weight of $KMnO _4$ in basic medium
$
=\frac{\text { Molecular weight of } KMnO _4 \text { }}{\text { No. of moles of electrons transferred }}
$
3. Equivalent weight of $KMnO _4$ in neutral medium
$
=\frac{\text { Molecular weight of } KMnO _{4 \text { }}}{\text { No. of moles of electrons transferred }}
$

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