Maharashtra BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions2 Marks
Question
Calculate the oxidation number of underlined atoms. H2SO4
✓
Answer
$H _2 SO _4$ Oxidation number of $H =+1$ Oxidation number of $O =-2$ $H _2 SO _4$ is a neutral molecule. $\therefore$ Sum of the oxidation numbers of all atoms of $H _2 SO _4=0$ $\therefore 2 \times($ Oxidation number of $H )+($ Oxidation number of $S )+4 \times($ Oxidation number of $O )$ $=0$ $\therefore 2 \times(+1)+$ (Oxidation number of $S)+4 \times(-2)=0$ $\therefore$ Oxidation number of $S+2-8=0$ $\therefore$ Oxidation number of $S$ in $H _2 SO _4=+6$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.