Question
Calculate the radius of Bohr’s fifth orbit for hydrogen atom.
rn = (0.0529nm) n2
For, n = 5 r5 = (0.0529nm) (5)2 r5 = 1.3225nmGenerate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\Delta_\text{f}\text{H}^\circ$ of KF = -560.8kJ mol-1, Sublimation energy of K = 87.8kJ mol-1, Dissociation energy of F, is 158.9kJ mol-1, Lattice energy of KF is -807.5kJ mol-1 and Ionisation energy of K is 414.2kJ mol-1.