MCQ
Carbinol is
- A${C_2}{H_5}OH$
- ✓$C{H_3}OH$
- C${(C{H_3})_2}CHOH$
- D$C{H_3}C{H_2}CH(OH)C{H_3}$
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$(i)$ $A$ and $D$ both form blue-violet colour with ninhydrin.
$(ii)$ Lassaigne extract of $\mathrm{C}$ give positive $\mathrm{AgNO}_{3}$ test and negative $\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ test.
$(iii)$ Lassaigne extract of $\mathrm{B}$ and D gives positive sodium nitroprusside test
Based on these observations which option is correct ?
$\mathrm{C}_{3} \mathrm{H}_{6} \stackrel{\mathrm{H}^{+} / \mathrm{H}_{2} \mathrm{O}}{\longrightarrow} A\xrightarrow[dil.\,KOH]{KIO} B+C$
The compounds $B$ and $C$ respectively are :